MHT CET · Maths · Functions
Let \(\mathrm{f}:[-1,3] \rightarrow \mathbb{R}\) be defined as
\(|x|+[x], -1 \leqslant x \lt 1 \ x+|x|, 1 \leqslant x \lt 2 \ x+[x],\) \(2 \leqslant x \leqslant 3\)
where \([t]\) denotes the greatest integer function.
Then f is discontinuous at
- A only two points
- B only three points
- C four or more points
- D only one point
Answer & Solution
Correct Answer
(B) only three points
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& \mathrm{f}(x)=\left\{\begin{array}{cc}
|x|+[x], & -1 \leq x \lt 1 \\
x+|x|, & 1 \leq x \lt 2 \\
x+[x], & 2 \leq x \leq 3
\end{array}\right. \\
& \therefore \quad \mathrm{f}(x)=\left\{\begin{array}{cc}
-(x+1), & -1 \leq x \lt 0 \\
x, & 0 \leq x \lt 1 \\
2 x, & 1 \leq x \lt 2 \\
x+2, & 2 \leq x \lt 3 \\
x+3, & x=3
\end{array}\right.
\end{aligned}\)
\(\therefore \quad \mathrm{f}(x)\) is discontinuous at \(x=0,1,3\).
& \mathrm{f}(x)=\left\{\begin{array}{cc}
|x|+[x], & -1 \leq x \lt 1 \\
x+|x|, & 1 \leq x \lt 2 \\
x+[x], & 2 \leq x \leq 3
\end{array}\right. \\
& \therefore \quad \mathrm{f}(x)=\left\{\begin{array}{cc}
-(x+1), & -1 \leq x \lt 0 \\
x, & 0 \leq x \lt 1 \\
2 x, & 1 \leq x \lt 2 \\
x+2, & 2 \leq x \lt 3 \\
x+3, & x=3
\end{array}\right.
\end{aligned}\)
\(\therefore \quad \mathrm{f}(x)\) is discontinuous at \(x=0,1,3\).
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