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MHT CET · Maths · Vector Algebra

Let \(\bar{a}, \overline{\mathrm{~b}}, \overline{\mathrm{c}}\) be three vectors such that \(\bar{a}+\overline{\mathrm{b}}+\overline{\mathrm{c}}=\overline{0},|\bar{a}|=3,|\overline{\mathrm{~b}}|=4\), \(|\overline{\mathrm{c}}|=5\), then \(\bar{a} \cdot \overline{\mathrm{~b}}+\overline{\mathrm{b}} \cdot \bar{c}+\overline{\mathrm{c}} \cdot \bar{a}=\)

  1. A \(25\)
  2. B \(-25\)
  3. C \(50\)
  4. D \(-50\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-25\)

Step-by-step Solution

Detailed explanation

\((\bar{a}+\overline{\mathrm{b}}+\overline{\mathrm{c}})^2 = |\bar{a}|^2 + |\overline{\mathrm{b}}|^2 + |\overline{\mathrm{c}}|^2 + 2(\bar{a} \cdot \overline{\mathrm{b}}+\overline{\mathrm{b}} \cdot \bar{c}+\overline{\mathrm{c}} \cdot \bar{a})\) \(0 = 3^2 + 4^2 + 5^2 + 2(\bar{a} \cdot \overline{\mathrm{b}}+\overline{\mathrm{b}} \cdot \bar{c}+\overline{\mathrm{c}} \cdot \bar{a})\)