MHT CET · Maths · Vector Algebra
Let \(\bar{a}, \overline{\mathrm{~b}}\) and \(\overline{\mathrm{c}}\) be vectors of magnitude 2,3 and 4 respectively. If \(\bar{a}\) is perpendicular to \((\overline{\mathrm{b}}+\overline{\mathrm{c}}), \overline{\mathrm{b}}\) is perpendicular to \((\overline{\mathrm{c}}+\bar{a})\) and \(\overline{\mathrm{c}}\) is perpendicular to ( \(\bar{a}+\bar{b}\) ), then the magnitude of \(\bar{a}+\overline{\mathrm{b}}+\overline{\mathrm{c}}\) is
- A 29
- B \(\sqrt{28}\)
- C \(\sqrt{29}\)
- D 28
Answer & Solution
Correct Answer
(C) \(\sqrt{29}\)
Step-by-step Solution
Detailed explanation
\( (\bar{a}+\bar{b}+\bar{c}) \cdot (\bar{a}+\bar{b}+\bar{c}) = |\bar{a}|^2 + |\bar{b}|^2 + |\bar{c}|^2 + 2(\bar{a}\cdot\bar{b} + \bar{b}\cdot\bar{c} + \bar{c}\cdot\bar{a}) \) \( \bar{a}\cdot(\bar{b}+\bar{c}) = 0 \implies \bar{a}\cdot\bar{b} + \bar{a}\cdot\bar{c} = 0 \)
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