ExamBro
ExamBro
MHT CET · Maths · Vector Algebra

Let \(\overline{\mathrm{a}}, \overline{\mathrm{b}}\) and \(\overline{\mathrm{c}}\) be vectors of magnitude 2,3 and 4 respectively. If \(\bar{a}\) is perpendicular to \((\bar{b}+\bar{c}), \bar{b}\) is perpendicular to \((\bar{c}+\bar{a})\) and \(\vec{c}\) is perpendicular to \((\bar{a}+\bar{b})\), then the magnitude of \(\overline{\mathrm{a}}+\overline{\mathrm{b}}+\overline{\mathrm{c}}\) is equal to

  1. A 29
  2. B \(\sqrt{29}\)
  3. C 26
  4. D \(\sqrt{26}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\sqrt{29}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \overline{\mathrm{a}} \perp(\overline{\mathrm{b}}+\overline{\mathrm{c}}), \quad \overline{\mathrm{b}} \perp(\overline{\mathrm{c}}+\overline{\mathrm{a}}) \text { and } \overline{\mathrm{c}} \perp(\overline{\mathrm{a}}+\overline{\mathrm{b}}) \\ & \Rightarrow \overline{\mathrm{a}} \cdot \overline{\mathrm{b}}+\overline{\mathrm{a}} \cdot \overline{\mathrm{c}}=0, \overline{\mathrm{~b}} \cdot \overline{\mathrm{c}}+\overline{\mathrm{b}} \cdot \overline{\mathrm{a}}=0, \overline{\mathrm{c}} \cdot \overline{\mathrm{a}}+\overline{\mathrm{c}} \cdot \overline{\mathrm{b}}=0 \\ & \Rightarrow \overline{\mathrm{a}} \cdot \overline{\mathrm{b}}+\overline{\mathrm{b}} \cdot \overline{\mathrm{c}}+\overline{\mathrm{c}} \cdot \overline{\mathrm{a}}=0\end{aligned}\)
\(\begin{aligned}|\overline{\mathrm{a}}+\overline{\mathrm{b}}+\overline{\mathrm{c}}|^2 & =|\overline{\mathrm{a}}|^2+|\overline{\mathrm{b}}|^2+|\overline{\mathrm{c}}|^2+2(\overline{\mathrm{a}} \cdot \overline{\mathrm{b}}+\overline{\mathrm{b}} \cdot \overline{\mathrm{c}}+\overline{\mathrm{c}} \cdot \overline{\mathrm{a}}) \\ & =2^2+3^2+4^2+2(0) \\ & =4+9+16\end{aligned}\)
\(\begin{array}{ll}\therefore \quad & |\bar{a}+\bar{b}+\bar{c}|^2=29 \\ & \Rightarrow|\bar{a}+\bar{b}+\bar{c}|=\sqrt{29}\end{array}\)