MHT CET · Maths · Probability
Let \(\mathrm{A}, \mathrm{B}\) and C be three events, which are pairwise independent and \(\overline{\mathrm{E}}\) denote the complement of an event E . If \(\mathrm{P}(\mathrm{A} \cap \mathrm{B} \cap \mathrm{C})=0\) and \(\mathrm{P}(\mathrm{C})\gt0\), then \(\mathrm{P}((\overline{\mathrm{A}} \cap \overline{\mathrm{B}}) / C)\) is equal to
- A \(\mathrm{P}(\mathrm{A})+\mathrm{P}(\overline{\mathrm{B}})\)
- B \(\mathrm{P}(\overline{\mathrm{A}})-\mathrm{P}(\overline{\mathrm{B}})\)
- C \(\mathrm{P}(\overline{\mathrm{A}})-\mathrm{P}(\mathrm{B})\)
- D \(\mathrm{P}(\overline{\mathrm{A}})+\mathrm{P}(\overline{\mathrm{B}})\)
Answer & Solution
Correct Answer
(C) \(\mathrm{P}(\overline{\mathrm{A}})-\mathrm{P}(\mathrm{B})\)
Step-by-step Solution
Detailed explanation
Given that \(\mathrm{A}, \mathrm{B}\) and C are pairwise independent.
\(\begin{aligned}
\therefore \quad & P(A \cap B \cap C)=0 \\
& \Rightarrow P(A) \cdot P(B) \cdot P(C)=0 \\
& \Rightarrow P(A) \cdot P(B)=0...(i) \\
& P((\bar{A} \cap \bar{B}) / C)=\frac{P(\bar{A} \cap \bar{B} \cap C)}{P(C)} \\
& =\frac{P(\bar{A}) \cdot P(\bar{B}) \cdot P(\bar{C})}{P(\bar{C})} \\
& =[1-P(A)] \cdot[1-P(B)] \\
& =1-P(A)-P(B)+P(A) P(B) \\
& =P(\bar{A})-P(B)...[From(i)]
\end{aligned}\)
\(\begin{aligned}
\therefore \quad & P(A \cap B \cap C)=0 \\
& \Rightarrow P(A) \cdot P(B) \cdot P(C)=0 \\
& \Rightarrow P(A) \cdot P(B)=0...(i) \\
& P((\bar{A} \cap \bar{B}) / C)=\frac{P(\bar{A} \cap \bar{B} \cap C)}{P(C)} \\
& =\frac{P(\bar{A}) \cdot P(\bar{B}) \cdot P(\bar{C})}{P(\bar{C})} \\
& =[1-P(A)] \cdot[1-P(B)] \\
& =1-P(A)-P(B)+P(A) P(B) \\
& =P(\bar{A})-P(B)...[From(i)]
\end{aligned}\)
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