MHT CET · Maths · Vector Algebra
Let \(\bar{a}\) and \(\bar{b}\) be two vectors such that. \(|\bar{a}|=1,|\bar{b}|=4, \bar{a} \cdot \bar{b}=2\). If \(\overline{\mathrm{c}}=(2 \bar{a} \times \bar{b})-3 \bar{b}\), then the angle between \(\overline{\mathrm{b}}\) and \(\overline{\mathrm{c}}\) is
- A \(\frac{\pi}{3}\)
- B \(\frac{\pi}{6}\)
- C \(\frac{3 \pi}{4}\)
- D \(\frac{5 \pi}{6}\)
Answer & Solution
Correct Answer
(D) \(\frac{5 \pi}{6}\)
Step-by-step Solution
Detailed explanation
\(\bar{a} \cdot \bar{b} = |\bar{a}| |\bar{b}| \cos \phi \implies 2 = 1 \cdot 4 \cos \phi \implies \cos \phi = \frac{1}{2}\) \( |(\bar{a} \times \bar{b})|^2 = |\bar{a}|^2 |\bar{b}|^2 (1 - \cos^2 \phi) = 1^2 \cdot 4^2 (1 - (1/2)^2) = 16 (3/4) = 12\)
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