MHT CET · Maths · Probability
Let \(A\) and \(B\) are independent events with \(P(B)=\frac{2}{5}, P(A \cup B)=\frac{11}{20}\), then \(\mathrm{P}\left(\mathrm{A}^{\prime} \mid \mathrm{B}\right)\) is root of the equation
- A \(4 x^2-7 x+3=0\)
- B \(4 x^2+7 x+3=0\)
- C \(4 x^2-3 x-7=0\)
- D \(6 x^2-5 x+1=0\)
Answer & Solution
Correct Answer
(A) \(4 x^2-7 x+3=0\)
Step-by-step Solution
Detailed explanation
\(P(A \cup B) = P(A) + P(B) - P(A)P(B)\) \( \frac{11}{20} = P(A) + \frac{2}{5} - P(A)\frac{2}{5} \implies \frac{11}{20} = \frac{3}{5}P(A) + \frac{2}{5} \)
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