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MHT CET · Maths · Application of Derivatives

In the 5. Mean Value Theorem, \(\mathrm{f}^{\prime}(\mathrm{c})=\frac{\mathrm{f}(\mathrm{b})-\mathrm{f}(\mathrm{a})}{\mathrm{b}-\mathrm{a}}\), if \(a=0, \mathrm{~b}=\frac{1}{2}\) and \(\mathrm{f}(x)=x(x-1)(x-2)\), then the value of c is

  1. A \(1-\frac{\sqrt{15}}{6}\)
  2. B \(1-\frac{\sqrt{13}}{6}\)
  3. C \(1-\frac{\sqrt{21}}{6}\)
  4. D \(1+\frac{\sqrt{21}}{6}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(1-\frac{\sqrt{21}}{6}\)

Step-by-step Solution

Detailed explanation

\(f(x) = x^3 - 3x^2 + 2x\) \(f'(x) = 3x^2 - 6x + 2\)