MHT CET · Maths · Properties of Triangles
In a triangle with one of the angles \(120^{\circ}\), the lengths of the sides form an A.P. If length of the greatest side is 7 m , then the area of the triangle is
- A \(\frac{15 \sqrt{3}}{4} \mathrm{~m}^2\)
- B \(\frac{15 \sqrt{3}}{2} \mathrm{~m}^2\)
- C \(\frac{15}{2} \mathrm{~m}^2\)
- D \(\frac{15}{4} \mathrm{~m}^2\)
Answer & Solution
Correct Answer
(A) \(\frac{15 \sqrt{3}}{4} \mathrm{~m}^2\)
Step-by-step Solution
Detailed explanation
\(c=7\), sides \(a=x-d\), \(b=x\) \(c^2 = a^2+b^2-2ab \cos C\)
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