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MHT CET · Maths · Properties of Triangles

In a triangle ABC , with usual notations, the sides \(a, \mathrm{~b}, \mathrm{c}\) are such that they are roots of the equation \(x^3-11 x^2+38 x-40=0\) then
\(\frac{\cos A}{a}+\frac{\cos B}{b}+\frac{\cos C}{c}=\)

  1. A \(\frac{9}{16}\)
  2. B \(\frac{3}{4}\)
  3. C 1
  4. D \(\frac{5}{16}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{9}{16}\)

Step-by-step Solution

Detailed explanation

\(a+b+c = 11\) \(ab+bc+ca = 38\)