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MHT CET · Maths · Properties of Triangles

In a triangle \(\mathrm{ABC}\), with usual notations, if \(\mathrm{m} \angle \mathrm{A}=60^{\circ}, \mathrm{b}=8, \mathrm{a}=6\) and \(\mathrm{B}=\sin ^{-1} x\), then \(x\) has the value

  1. A \(\frac{\sqrt{3}}{2}\)
  2. B \(\frac{2}{\sqrt{3}}\)
  3. C \(2 \sqrt{3}\)
  4. D \(\frac{1}{2 \sqrt{3}}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{2}{\sqrt{3}}\)

Step-by-step Solution

Detailed explanation

By sine rule, we get
\(
\begin{aligned}
& \frac{\sin \mathrm{A}}{\mathrm{a}}=\frac{\sin \mathrm{B}}{\mathrm{b}} \\
& \Rightarrow \frac{\sin 60^{\circ}}{6}=\frac{x}{8} \\
& \Rightarrow x=\frac{\sqrt{3}}{2} \times \frac{8}{6} \\
& \Rightarrow x=\frac{2}{\sqrt{3}}
\end{aligned}
\)