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MHT CET · Maths · Properties of Triangles

In a triangle ABC with usual notations if \(\angle A=30^{\circ}\), then the value of \(\left(1+\frac{a}{c}+\frac{b}{c}\right)\left(1+\frac{c}{b}-\frac{a}{b}\right)=\)

  1. A \(\sqrt{3}-2\)
  2. B \(2+\sqrt{5}\)
  3. C \(\sqrt{3}+2\)
  4. D \(2-\sqrt{5}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\sqrt{3}+2\)

Step-by-step Solution

Detailed explanation

\(\left(1+\frac{a}{c}+\frac{b}{c}\right)\left(1+\frac{c}{b}-\frac{a}{b}\right) = \frac{(c+a+b)}{c} \frac{(b+c-a)}{b}\) \(= \frac{(b+c)^2 - a^2}{bc} \)