MHT CET · Maths · Properties of Triangles
In a triangle ABC with usual notations if, \(\cot \frac{A}{2}=\frac{b+c}{a}\), then the triangle \(A B C\) is
- A an isosceles triangle.
- B an equilateral triangle.
- C a right angled triangle.
- D an obtuse angled triangle.
Answer & Solution
Correct Answer
(C) a right angled triangle.
Step-by-step Solution
Detailed explanation
\(\frac{\cos \frac{A}{2}}{\sin \frac{A}{2}} = \frac{b+c}{a}\) \(\frac{\cos \frac{A}{2}}{\sin \frac{A}{2}} = \frac{2R \sin B + 2R \sin C}{2R \sin A} = \frac{\sin B + \sin C}{\sin A}\)
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