MHT CET · Maths · Properties of Triangles
In a triangle ABC , with usual notations if
\(\frac{2 \cos \mathrm{~A}}{a}+\frac{\cos \mathrm{B}}{\mathrm{b}}+\frac{2 \cos \mathrm{C}}{\mathrm{c}}=\frac{a}{\mathrm{bc}}+\frac{\mathrm{b}}{c a}\)
then \(\angle \mathrm{A}=\)
- A \(\frac{\pi}{2}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{3}\)
- D \(\frac{\pi}{6}\)
Answer & Solution
Correct Answer
(A) \(\frac{\pi}{2}\)
Step-by-step Solution
Detailed explanation
\( \frac{2 \cos A}{a}+\frac{\cos B}{b}+\frac{2 \cos C}{c}=\frac{a^2+b^2}{abc} \) Multiply by \(2abc\) and substitute cosine rules:
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