MHT CET · Maths · Properties of Triangles
In a triangle ABC , with usual notations, \(\cot \left(\frac{A+B}{2}\right) \cdot \tan \left(\frac{A-B}{2}\right)=\)
- A \(\frac{a+b}{a-b}\)
- B \(\frac{a-b}{a+b}\)
- C \(\frac{a}{a+b}\)
- D \(\frac{\mathrm{b}}{a-\mathrm{b}}\)
Answer & Solution
Correct Answer
(B) \(\frac{a-b}{a+b}\)
Step-by-step Solution
Detailed explanation
\(= \cot \left(\frac{\pi - C}{2}\right) \cdot \tan \left(\frac{A-B}{2}\right)\) \(= \tan \left(\frac{C}{2}\right) \cdot \tan \left(\frac{A-B}{2}\right)\)
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