MHT CET · Maths · Properties of Triangles
In a triangle ABC , with usual notations, \(3 \mathrm{~b}=\mathrm{a}+\mathrm{c}\), then \(\cot \frac{\mathrm{A}}{2} \cdot \cot \frac{\mathrm{c}}{2}=\)
- A \(1\)
- B \(2\)
- C \(\frac{1}{2}\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
\(\cot \frac{A}{2} \cdot \cot \frac{C}{2} = \frac{s}{s-b}\) \(s = \frac{a+b+c}{2}\)
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