MHT CET · Maths · Properties of Triangles
In a triangle ABC , the sides \(a, \mathrm{~b}, \mathrm{c}\) are such that they are the roots of the equation \(x^3-11 x^2+38 x-40=0\) Then \(\frac{\cos \mathrm{A}}{a}+\frac{\cos \mathrm{B}}{\mathrm{b}}+\frac{\cos \mathrm{C}}{\mathrm{c}}=\)
- A \(\frac{3}{4}\)
- B \(1\)
- C \(\frac{9}{16}\)
- D \(\frac{1}{16}\)
Answer & Solution
Correct Answer
(C) \(\frac{9}{16}\)
Step-by-step Solution
Detailed explanation
\(a+b+c = 11\) \(ab+bc+ca = 38\)
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