MHT CET · Maths · Properties of Triangles
In a triangle \(A B C\), with usual notations, if
\(\frac{b+c}{11}=\frac{c+a}{12}=\frac{a+b}{13}\) Then \(\cos A: \cos B: \cos C\) is
- A \(7: 19: 25\)
- B \(19: 7: 25\)
- C \(12: 14: 20\)
- D \(19: 25: 20\)
Answer & Solution
Correct Answer
(A) \(7: 19: 25\)
Step-by-step Solution
Detailed explanation
\(\frac{b+c}{11}=\frac{c+a}{12}=\frac{a+b}{13}=k\) \(b+c=11k, c+a=12k, a+b=13k\)
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