MHT CET · Maths · Properties of Triangles
In a triangle \(A B C\), with usual notations, if \(a=5, b=4, \cos (A-B)=\frac{31}{32}\), then \(c=\)
- A 6
- B 7
- C 5
- D 2
Answer & Solution
Correct Answer
(A) 6
Step-by-step Solution
Detailed explanation
\(\tan^2\left(\frac{A-B}{2}\right) = \frac{1-\cos(A-B)}{1+\cos(A-B)} = \frac{1-31/32}{1+31/32} = \frac{1/32}{63/32} = \frac{1}{63}\) \(\tan\left(\frac{A-B}{2}\right) = \frac{1}{\sqrt{63}} = \frac{1}{3\sqrt{7}}\)
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