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MHT CET · Maths · Properties of Triangles

In a triangle \(A B C\), with usual notations, if \(a=5, b=4, \cos (A-B)=\frac{31}{32}\), then \(c=\)

  1. A 6
  2. B 7
  3. C 5
  4. D 2
Verified Solution

Answer & Solution

Correct Answer

(A) 6

Step-by-step Solution

Detailed explanation

\(\tan^2\left(\frac{A-B}{2}\right) = \frac{1-\cos(A-B)}{1+\cos(A-B)} = \frac{1-31/32}{1+31/32} = \frac{1/32}{63/32} = \frac{1}{63}\) \(\tan\left(\frac{A-B}{2}\right) = \frac{1}{\sqrt{63}} = \frac{1}{3\sqrt{7}}\)