MHT CET · Maths · Properties of Triangles
In a triangle \(A B C\), with usual notations, \((a+b+c)(a+b-c)=3 a b\), then \(\angle \mathrm{C}=\)
- A \(\frac{\pi}{2}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{3}\)
- D \(\frac{\pi}{6}\)
Answer & Solution
Correct Answer
(C) \(\frac{\pi}{3}\)
Step-by-step Solution
Detailed explanation
\((a+b)^2 - c^2 = 3ab\) \(a^2 + 2ab + b^2 - c^2 = 3ab\)
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