MHT CET · Maths · Properties of Triangles
In a triangle \(A B C\), with usual notation, \(\angle B=\pi / 3, \angle C=\pi / 4 . D\) divides \(B C\) internally in the ratio 1:3 then \(\frac{\sin \angle \mathrm{BAD}}{\sin \angle \mathrm{CAD}}\)
- A \(\left(x \frac{\mathrm{dy}}{\mathrm{d} x}-\mathrm{y}\right)^2\)
- B \(\left(\mathrm{y} \frac{\mathrm{d} x}{\mathrm{dy}}-x\right)^2\)
- C \(\left(x \frac{\mathrm{dy}}{\mathrm{d} x}+\mathrm{y}\right)^2\)
- D \(\left(\mathrm{y} \frac{\mathrm{d} x}{\mathrm{dy}}+x\right)^2\)
Answer & Solution
Correct Answer
(A) \(\left(x \frac{\mathrm{dy}}{\mathrm{d} x}-\mathrm{y}\right)^2\)
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