MHT CET · Maths · Probability
In a meeting \(70 \%\) of the members favour and \(30 \%\) oppose a certain proposal. A member is selected at random. We take \(\mathrm{X}=0\) if he opposed the proposal and we take \(\mathrm{X}=1\), if the member is in favour. Then variance of \(X\) is
- A \(\frac{5}{17}\)
- B \(\frac{2}{15}\)
- C \(\frac{21}{100}\)
- D \(\frac{23}{100}\)
Answer & Solution
Correct Answer
(C) \(\frac{21}{100}\)
Step-by-step Solution
Detailed explanation
\(P(X=1) = 0.7\) \(P(X=0) = 0.3\)
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