MHT CET · Maths · Statistics
In a meeting \(60 \%\) of the members favour and \(40 \%\) oppose a certain proposal. A member is selected at random and we take \(\mathrm{X}=0\) if the opposed and \(\mathrm{X}=1\) if he is in favour, then Var \(\mathrm{X}=\)
- A 0.36
- B 0.24
- C 0.6
- D 0.06
Answer & Solution
Correct Answer
(B) 0.24
Step-by-step Solution
Detailed explanation
From the given data, we write
\(\text {Variance }=\Sigma \mathrm{p}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}}^2-\left(\sum \mathrm{p}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}}\right)^2=0.6-(0.6)^2=0.6\) \(-~0.36=0.24
\)
\(\text {Variance }=\Sigma \mathrm{p}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}}^2-\left(\sum \mathrm{p}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}}\right)^2=0.6-(0.6)^2=0.6\) \(-~0.36=0.24
\)
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