MHT CET · Maths · Probability
In a game a man wins \(₹ 40\) if he gets 5 or 6 on a throw of a fair die and loses ₹ 20 for getting any other number on the die. If he decides to throw the die either till he gets a five or six or to a maximum of three throws, then his expected gain/loss (in rupees) is
- A \(-10\)
- B 10
- C 0
- D 1
Answer & Solution
Correct Answer
(C) 0
Step-by-step Solution
Detailed explanation
\(P(\text{win}) = \frac{2}{6} = \frac{1}{3}\) \(P(\text{lose}) = \frac{4}{6} = \frac{2}{3}\)
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