MHT CET · Maths · Differential Equations
In a culture bacteria count is \(1,00,000\) initially. The number increases by \(10 \%\) in first 2 hours. In how many hours will the count reach \(2,00,000\), if the rate of growth of bacteria is proportional to the number present?
- A \(\frac{2 \log \left(\frac{11}{10}\right)}{\log 2}\)
- B \(\frac{\log \left(\frac{11}{10}\right)}{\log 2}\)
- C \(\frac{2 \log 2}{\log \left(\frac{11}{10}\right)}\)
- D \(\frac{\log (2)}{\log \left(\frac{11}{10}\right)}\)
Answer & Solution
Correct Answer
(C) \(\frac{2 \log 2}{\log \left(\frac{11}{10}\right)}\)
Step-by-step Solution
Detailed explanation
\(N(t) = N_0 r^t\) \(1.1 N_0 = N_0 r^2 \implies r^2 = 1.1\)
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