MHT CET · Maths · Differential Equations
In a bank, the principal increases continuously at a rate of \(x \%\) per year. Then the rate, \(x\), if ₹100 double itself in 10 years, is
\((\log 2=0.6931)\)
- A \(6.93 \%\)
- B \(9 \cdot 63 \%\)
- C \(6.09 \%\)
- D \(3.69 \%\)
Answer & Solution
Correct Answer
(A) \(6.93 \%\)
Step-by-step Solution
Detailed explanation
\(A = P e^{rt}\) \(2P = P e^{(x/100) \cdot 10}\)
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