MHT CET · Maths · Differentiation
If \(\mathrm{y}=y=e^{\cos ^{-1}\left(\sqrt{1-x^2}\right)}\), then \(\frac{1}{y} \frac{d y}{d x}\)
- A \(\frac{\sqrt{1-x^2}}{2}\)
- B \(\sqrt{1-x^2}\)
- C \(\frac{1}{\sqrt{1-x^2}}\)
- D \(\frac{1}{2 \sqrt{1-x^2}}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{\sqrt{1-x^2}}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & y=e^{\cos ^{-1}\left(\sqrt{1-x^2}\right)} \\ & \Rightarrow \log _e y=\cos ^{-1} \sqrt{1-x^2}\end{aligned}\)
Diff. w.r.t. \(\mathrm{x}\)
\(\frac{1}{y} \cdot \frac{d y}{d x}=\frac{-1}{\sqrt{1-\left(1-x^2\right)}} \times \frac{1}{2 \sqrt{1-x^2}} \times(-2 x)=\frac{2 x}{2 \sqrt{x^2} \sqrt{1-x^2}}=\frac{1}{\sqrt{1-x^2}}\)
Diff. w.r.t. \(\mathrm{x}\)
\(\frac{1}{y} \cdot \frac{d y}{d x}=\frac{-1}{\sqrt{1-\left(1-x^2\right)}} \times \frac{1}{2 \sqrt{1-x^2}} \times(-2 x)=\frac{2 x}{2 \sqrt{x^2} \sqrt{1-x^2}}=\frac{1}{\sqrt{1-x^2}}\)
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