MHT CET · Maths · Differentiation
If \(y=\left(x^x\right) x\), then \(\frac{d y}{d x}=\)
- A \(x^{x^2}(1+\log x)\)
- B \(x \cdot x^{x^2}(1+\log x)\)
- C \(x^{x^2}(1+2 \log x)\)
- D \(x \cdot x^{x^2}(2 \log x+1)\)
Answer & Solution
Correct Answer
(D) \(x \cdot x^{x^2}(2 \log x+1)\)
Step-by-step Solution
Detailed explanation
\(y=\left(x^x\right) x \Rightarrow \log y=x \log x^x=x^2 \log x\)
Differentiating both sides w.r.t. \(\mathrm{x}\)
\(\begin{aligned} & \frac{1}{y} \cdot \frac{d y}{d x}=x^2 \times \frac{1}{x}+2 x \times \log x \\ & \Rightarrow \frac{d y}{d x}=y(x+2 x \log x) \\ & \Rightarrow \frac{d y}{d x}=\left(x^x\right)^x \cdot x(1+2 \log x) \\ & \Rightarrow \frac{d y}{d x}=x^{x^2} \cdot x(1+2 \log x)\end{aligned}\)
Differentiating both sides w.r.t. \(\mathrm{x}\)
\(\begin{aligned} & \frac{1}{y} \cdot \frac{d y}{d x}=x^2 \times \frac{1}{x}+2 x \times \log x \\ & \Rightarrow \frac{d y}{d x}=y(x+2 x \log x) \\ & \Rightarrow \frac{d y}{d x}=\left(x^x\right)^x \cdot x(1+2 \log x) \\ & \Rightarrow \frac{d y}{d x}=x^{x^2} \cdot x(1+2 \log x)\end{aligned}\)
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