MHT CET · Maths · Application of Derivatives
If \(\mathrm{y}=\alpha \log x+\beta x^3-x\) has extreme values at \(x=-1\) and \(x=1\), then \(\alpha\) and \(\beta\) are respectively
- A 0 and \(\frac{1}{3}\)
- B 0 and \(\frac{-1}{3}\)
- C \(\frac{-1}{3}\) and \(\frac{1}{3}\)
- D \(\frac{1}{3}\) and \(\frac{1}{3}\)
Answer & Solution
Correct Answer
(A) 0 and \(\frac{1}{3}\)
Step-by-step Solution
Detailed explanation
\(\frac{dy}{dx}=\frac{\alpha}{x}+3\beta x^2-1\) At \(x=1\): \(\frac{\alpha}{1}+3\beta (1)^2-1=0 \implies \alpha+3\beta=1\)
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