MHT CET · Maths · Differentiation
If \(y=\cos \left(\sin x^2\right)\), then \(\frac{d y}{d x} a t x=\sqrt{\frac{\pi}{2}}\) is
- A \(-2\)
- B \(0\)
- C \(2\)
- D \(-1\)
Answer & Solution
Correct Answer
(B) \(0\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & y=\cos \left(\sin x^2\right) \\ & \Rightarrow \frac{d y}{d x}=-\sin \left(\sin x^2\right) \cdot \cos x^2 \cdot 2 x \\ & \frac{d y}{d x}\left(a t x \sqrt{\frac{\pi}{2}}\right)=-\sin \left(\sin \frac{\pi}{2}\right) \cdot \cos \cdot 2 \times \sqrt{\frac{\pi}{2}} \\ & =-\sin (1) \times 0 \times 2 \times \sqrt{\frac{\pi}{2}}=0\end{aligned}\)
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