MHT CET · Maths · Differentiation
If \(\mathrm{y}=\log _{\mathrm{e}} x^3+3 \sin ^{-1} x+\mathrm{k} x^2\) and \(\mathrm{y}^{\prime}\left(\frac{1}{2}\right)=2 \sqrt{3}\), then \(\mathrm{k}=\)
- A \(6\)
- B \(-6\)
- C \(2 \sqrt{3}\)
- D 1
Answer & Solution
Correct Answer
(B) \(-6\)
Step-by-step Solution
Detailed explanation
\(y' = \frac{\mathrm{d}}{\mathrm{d}x}(3\log_e x) + \frac{\mathrm{d}}{\mathrm{d}x}(3\sin^{-1} x) + \frac{\mathrm{d}}{\mathrm{d}x}(\mathrm{k}x^2)\) \(y' = \frac{3}{x} + \frac{3}{\sqrt{1-x^2}} + 2\mathrm{k}x\)
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