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MHT CET · Maths · Differentiation

If \(y=\log \left[\mathrm{e}^{5 x}\left(\frac{3 x-4}{x+5}\right)^{\frac{4}{3}}\right]\), then \(\frac{\mathrm{d} y}{\mathrm{~d} x}\) is equal to

  1. A \(5+\frac{4}{3 x-4}-\frac{4}{3(x+5)}\)
  2. B \(5+\frac{4}{3(3 x-4)}-\frac{4}{3(x+5)}\)
  3. C \(5 x+\frac{4}{3 x-4}-\frac{4}{3(x+5)}\)
  4. D \(5+\frac{12}{3 x-4}-\frac{4}{(x+5)}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(5+\frac{4}{3 x-4}-\frac{4}{3(x+5)}\)

Step-by-step Solution

Detailed explanation

\(y =\log \left[\mathrm{e}^{5 x}\left(\frac{3 x-4}{x+5}\right)^{\frac{4}{3}}\right] \)
\( \therefore y =5 x \log \mathrm{e}+\frac{4}{3} \log (3 x-4)-\frac{4}{3} \log (x+5) \)
\( \therefore \frac{\mathrm{d} y}{\mathrm{~d} x} =5+\frac{4}{3(3 x-4)} \times 3-\frac{4}{3(x+5)} \times 1 \)
\( =5+\frac{4}{(3 x-4)}-\frac{4}{3(x+5)}\)