MHT CET · Maths · Differentiation
If \(y=e^{4 x} \cos 5 x\), then \(\frac{d^{2} y}{d x^{2}}\) at \(x=0\) is
- A \(-9\)
- B 9
- C 8
- D \(-8\)
Answer & Solution
Correct Answer
(A) \(-9\)
Step-by-step Solution
Detailed explanation
Given \(y=e^{4 x} \cos 5 x\)
\(\therefore \frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{e}^{4 \mathrm{x}}(-5 \sin 5 \mathrm{x})+\cos 5 \mathrm{x}\left(4 \mathrm{e}^{4 \mathrm{x}}\right)\) \(=\mathrm{e}^{4 \mathrm{x}}(-5 \sin 5 \mathrm{x}+4 \cos 5 \mathrm{x}) \)
\( \frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}=\left[\mathrm{e}^{4 \mathrm{x}}(-25 \cos 5 \mathrm{x}-20 \sin 5 \mathrm{x})\right]+[(-5 \sin 5 \mathrm{x}\) \(+~4 \cos 5 \mathrm{x}) \cdot(4 \mathrm{e}^{4} \mathrm{x})] \)
\( \left(\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}\right)_{\mathrm{x}=0}=-25+(4 \times 4)=-25+16=-9\)
\(\therefore \frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{e}^{4 \mathrm{x}}(-5 \sin 5 \mathrm{x})+\cos 5 \mathrm{x}\left(4 \mathrm{e}^{4 \mathrm{x}}\right)\) \(=\mathrm{e}^{4 \mathrm{x}}(-5 \sin 5 \mathrm{x}+4 \cos 5 \mathrm{x}) \)
\( \frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}=\left[\mathrm{e}^{4 \mathrm{x}}(-25 \cos 5 \mathrm{x}-20 \sin 5 \mathrm{x})\right]+[(-5 \sin 5 \mathrm{x}\) \(+~4 \cos 5 \mathrm{x}) \cdot(4 \mathrm{e}^{4} \mathrm{x})] \)
\( \left(\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}\right)_{\mathrm{x}=0}=-25+(4 \times 4)=-25+16=-9\)
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