MHT CET · Maths · Differentiation
If \(y=e^{4 x}+2 e^{-x}\) satisfies the equation \(\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}+A \frac{\mathrm{d} y}{\mathrm{~d} x}+\mathrm{By}=o\) then values of and \(B\) are respectively
- A 3,4
- B -3,-4
- C 4,3
- D -4,-3
Answer & Solution
Correct Answer
(B) -3,-4
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & y=e^{4 x}+2 e^{-x} \\ & \Rightarrow \frac{\mathrm{d} y}{\mathrm{~d} x}=4 \cdot e^{4 x}-2 \cdot e^{-x} \\ & \Rightarrow \frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}=16 e^{4 x}+2 e^{-x} \\ & \Rightarrow \frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}-3 \frac{\mathrm{d} y}{\mathrm{~d} x}-4 y=0 \\ & \Rightarrow A=-3 \text { and } B=-4\end{aligned}\)
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