ExamBro
ExamBro
MHT CET · Maths · Differentiation

If \(y=\mathrm{A} \cos \mathrm{n} x+\mathrm{B} \sin \mathrm{n} x\), then \(\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}=\)

  1. A \(-\mathrm{n}^2 y\)
  2. B \(\mathrm{n}^2 y\)
  3. C \(\mathrm{n}^2 x\)
  4. D \(\mathrm{n}^2 x^2\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(-\mathrm{n}^2 y\)

Step-by-step Solution

Detailed explanation

\(y=A \cos n x+B \sin n x ...(i)\)
Differentiating w.r.to \(x\), we get
\(\begin{aligned}
& \frac{d y}{d x}=-A n(\sin n x)+B n \cos n x \\
& \frac{d y}{d x}=-n A \sin n x+n \cdot B \cos n x
\end{aligned}\)
Again differentiating w.r.to \(x\), we get
\(\begin{aligned}
\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2} & =-\mathrm{n}^2 A \cos n x-n^2 B \sin n x \\
& =-n^2[A \cos n x+B \sin n x] \\
\frac{\mathrm{d}^2 y}{d x^2} & =-n^2 y
\end{aligned}\)
...[from (i)]