MHT CET · Maths · Application of Derivatives
If \(y=4 x-5\) is tangent to the curve \(y^2=p x^3+q\) at \((2,3)\), then
- A \(p=2, q=-7\)
- B \(p=2, q=7\)
- C \(p=-2, q=7\)
- D \(p=-2, q=-7\)
Answer & Solution
Correct Answer
(A) \(p=2, q=-7\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & (2,3) \text { lies on } y^2=p x^3+q \\ & \Rightarrow 3^2=P \times 2^3+q\end{aligned}\)
from (i) and (ii) \(q=-7\)
from (i) and (ii) \(q=-7\)
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