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MHT CET · Maths · Differentiation

If \(y=3 e^{5 x}+5 e^{3 x}, \quad\) then \(\frac{d^{2} y}{d x^{2}}-8 \frac{d y}{d x}=\)

  1. A \(-10 y\)
  2. B \(15 y\)
  3. C \(-15 y\)
  4. D \(10 y\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(-15 y\)

Step-by-step Solution

Detailed explanation

\(y=3 e^{5 x}+5 e^{3 x} \)
\( \therefore \frac{d y}{d x}=3 e^{5 x} \times 5+5 e^{3 x} \times 3=15 e^{5 x}+15 e^{3 x} \)
\( \frac{d^{2} y}{d x^{2}} =15 e^{5 x} \times 5+15 e^{3 x} \times 3 \)
\( =75 e^{5 x}+45 e^{3 x} \)
\( \therefore \frac{d^{2} y}{d x^{2}}-8 \frac{d y}{d x} =75 e^{5 x}+45 e^{3 x}-8\left(15 e^{5 x}+15 e^{3 x}\right) \)
\( =75 e^{5 x}+45 e^{3 x}-120 e^{5 x}-120 e^{3 x} \)
\( =-45 e^{5 x}-75 e^{3 x} \)
\( =-15\left(3 e^{5 x}+5 e^{3 x}\right) \)
\( =-15 y\)