MHT CET · Maths · Inverse Trigonometric Functions
If \(\mathrm{y}=\sin ^2\left(\cot ^{-1}\left(\sqrt{\frac{1-x}{1+x}}\right)\right)\), then \(\frac{\mathrm{dy}}{\mathrm{d} x}=\)
- A \(-1\)
- B \(1\)
- C \(-\frac{1}{4}\)
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
Let \(x = \cos\theta\). \(y = \sin^2\left(\cot^{-1}\left(\sqrt{\frac{1-\cos\theta}{1+\cos\theta}}\right)\right)\)
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