ExamBro
ExamBro
MHT CET · Maths · Differentiation

If \(y=1+x+\frac{x^{2}}{2 !}+\frac{x^{3}}{3 !}+\ldots \ldots\) then \(\frac{d y}{d x}=\)

  1. A \(y-1\)
  2. B \(y+1\)
  3. C \(y^{2}-1\)
  4. D \(y\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(y\)

Step-by-step Solution

Detailed explanation

Given
\(y=1+x+\frac{x^{2}}{2 !}+\frac{x^{3}}{3 !}+\ldots\)
\(\therefore \frac{d y}{d x}=e^{x}=y\)
\(\Rightarrow y=e^{x} \)