MHT CET · Maths · Trigonometric Ratios & Identities
If \(y=\tan ^{-1}\left(\frac{\sin 2 x}{1+\cos 2 x}\right)\), then \(\frac{d y}{d x}=\)
- A 1
- B 0
- C \(-1\)
- D 2
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
Given \(y=\tan ^{-1}\left(\frac{\sin 2 x}{1+\cos 2 x}\right)=\tan ^{-1}\left(\frac{2 \sin x \cos x}{2 \cos ^{2} x}\right)=\tan ^{-1}(\tan x)\)
\(\therefore \quad y=x \Rightarrow \frac{d y}{d x}=1\)
\(\therefore \quad y=x \Rightarrow \frac{d y}{d x}=1\)
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