MHT CET · Maths · Differentiation
If \(y=\tan ^{-1} \sqrt{\frac{1+\cos x}{1-\cos x}}\), then \(\frac{d y}{d x}\) is
- A \(\frac{3}{2}\)
- B \(\frac{-1}{2}\)
- C \(-1\)
- D 1
Answer & Solution
Correct Answer
(B) \(\frac{-1}{2}\)
Step-by-step Solution
Detailed explanation
\(y=\tan ^{-1} \sqrt{\frac{1+\cos x}{1-x \cos x}}=\tan ^{-1} \sqrt{\frac{2 \cos ^2 \frac{x}{2}}{2 \sin ^2 \frac{x}{2}}}=\) (\(\tan ^{-1}\left(\cot \frac{x}{2}\right) \)
\( \Rightarrow y=\tan ^{-1} \tan \left(\frac{\pi}{2}-\frac{x}{2}\right)=\frac{\pi}{2}-\frac{x}{2}\)
Differentiating
\(\frac{\mathrm{dy}}{\mathrm{dx}}=0-\frac{1}{2}=\frac{-1}{2}\)
\( \Rightarrow y=\tan ^{-1} \tan \left(\frac{\pi}{2}-\frac{x}{2}\right)=\frac{\pi}{2}-\frac{x}{2}\)
Differentiating
\(\frac{\mathrm{dy}}{\mathrm{dx}}=0-\frac{1}{2}=\frac{-1}{2}\)
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