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MHT CET · Maths · Differentiation

If \(y=\tan ^{-1} \sqrt{\frac{1+\cos x}{1-\cos x}}\), then \(\frac{d y}{d x}\) is

  1. A \(\frac{3}{2}\)
  2. B \(\frac{-1}{2}\)
  3. C \(-1\)
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{-1}{2}\)

Step-by-step Solution

Detailed explanation

\(y=\tan ^{-1} \sqrt{\frac{1+\cos x}{1-x \cos x}}=\tan ^{-1} \sqrt{\frac{2 \cos ^2 \frac{x}{2}}{2 \sin ^2 \frac{x}{2}}}=\) (\(\tan ^{-1}\left(\cot \frac{x}{2}\right) \)
\( \Rightarrow y=\tan ^{-1} \tan \left(\frac{\pi}{2}-\frac{x}{2}\right)=\frac{\pi}{2}-\frac{x}{2}\)
Differentiating
\(\frac{\mathrm{dy}}{\mathrm{dx}}=0-\frac{1}{2}=\frac{-1}{2}\)