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MHT CET · Maths · Trigonometric Ratios & Identities

If \(\cos x+\cos y=-\cos \alpha, \sin x+\sin y=-\sin \alpha\), then \(\cot \left(\frac{x+y}{2}\right)=\)

  1. A \(-\cot \propto\)
  2. B \(\cot \propto\)
  3. C \(-\tan \propto\)
  4. D \(\tan \propto\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\cot \propto\)

Step-by-step Solution

Detailed explanation

Given \(\cos x+\cos y=-\cos \alpha\) and \(\sin x+\sin y=-\sin \alpha\)
\(2 \cos \left(\frac{x+y}{2}\right) \cos \left(\frac{x-y}{2}\right)=-\cos \alpha\) ...(1) and
\(2 \sin \left(\frac{x+y}{2}\right) \cos \left(\frac{x-y}{2}\right)=-\sin \alpha\) ...(2)
Divided equation (1) by equation (2)
\(\cot \left(\frac{x+y}{2}\right)=\cot \alpha\)
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