MHT CET · Maths · Differentiation
If \(\log (x+y)=\log x y+3\), then \(\frac{\mathrm{d} y}{\mathrm{~d} x}=\)
- A \(\left(\frac{y}{x}\right)^2\)
- B \(-\left(\frac{x}{y}\right)^2\)
- C \(-\left(\frac{y}{x}\right)^2\)
- D \(\left(\frac{x}{y}\right)^2\)
Answer & Solution
Correct Answer
(C) \(-\left(\frac{y}{x}\right)^2\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \log (x+y)=\log x y+3 \\ & \Rightarrow \log \left(\frac{x+y}{x y}\right)=3 \\ & \Rightarrow \frac{x+y}{x y}=e^3 \\ & \Rightarrow \frac{1}{y}+\frac{1}{x}=e^3 \\ & \text { Diff } \frac{-1}{y^2} \frac{\mathrm{d} y}{\mathrm{~d} x}-\frac{1}{x^2}=0 \\ & \Rightarrow \frac{\mathrm{d} y}{\mathrm{~d} x}=-\frac{y^2}{x^2}\end{aligned}\)
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