MHT CET · Maths · Trigonometric Equations
If \(\sin (x+y)+\cos (x+y)=\sin \left[\cos ^{-1}\left(\frac{1}{3}\right)\right]\), then \(\frac{d y}{d x}=\)
- A \(\frac{1}{2}\)
- B -1
- C 1
- D 0
Answer & Solution
Correct Answer
(B) -1
Step-by-step Solution
Detailed explanation
\(\sin (x+y)+\cos (x+y)=\sin \left[\cos ^{-1}\left(\frac{1}{3}\right)\right]\) Let \(\theta = \cos^{-1}\left(\frac{1}{3}\right)\). Then \(\cos \theta = \frac{1}{3}\).
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