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MHT CET · Maths · Application of Derivatives

If \(x+\mathrm{y}=6, x \geqslant 0, y \geqslant 0\), then the maximum value of \(x^2 \mathrm{y}\) is

  1. A 30
  2. B 32
  3. C 34
  4. D 36
Verified Solution

Answer & Solution

Correct Answer

(B) 32

Step-by-step Solution

Detailed explanation

\(y = 6-x\) \(f(x) = x^2(6-x) = 6x^2 - x^3\)
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