MHT CET · Maths · Application of Derivatives
If \(x+\mathrm{y}=6, x \geqslant 0, y \geqslant 0\), then the maximum value of \(x^2 \mathrm{y}\) is
- A 30
- B 32
- C 34
- D 36
Answer & Solution
Correct Answer
(B) 32
Step-by-step Solution
Detailed explanation
\(y = 6-x\) \(f(x) = x^2(6-x) = 6x^2 - x^3\)
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