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MHT CET · Maths · Differentiation

If \(x y=\tan ^{-1}(x y)+\cot ^{-1}(x y)\), then \(\left(\frac{\mathrm{d} y}{\mathrm{~d} x}\right)_{(4,2)}=(\) where \(x, y \in I R)\)

  1. A \(\frac{-1}{2}\)
  2. B -2
  3. C 2
  4. D \(\frac{1}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{-1}{2}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned}
& x y=\tan ^{-1}(x y)+\cot ^{-1}(x y) \\
& \Rightarrow x y=\frac{\pi}{2}
\end{aligned}\)
diff. we get \(1 \cdot y+x \cdot \frac{d y}{d x}=0\)
\(\begin{aligned}
& \Rightarrow \frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{-y}{x} \\
& \Rightarrow \frac{\mathrm{d} y}{\mathrm{~d} x} \text { at, }(4,2)=\frac{-2}{4}=\frac{-1}{2}
\end{aligned}\)