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MHT CET · Maths · Indefinite Integration

If \(\int x^{x}(1+\log x) d x=k x^{x}+c\), then \(k=\)

  1. A \(\log _{e} e\)
  2. B \(\log _{e}\left(\frac{1}{e^{2}}\right)\)
  3. C \(\log _{e}\left(e^{2}\right)\)
  4. D \(\log _{e}\left(\frac{1}{e}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\log _{e} e\)

Step-by-step Solution

Detailed explanation

Let \(I=\int x^{x}(1+\log x) d x\)
Put \(x^{x}=t \Rightarrow e^{x \log x}=t \Rightarrow e^{x \log x}(1+\log x)\) \(d x=d t\) \(\therefore x^{x}(1+\log x) d x=d t\)
Thus, \(I=\int d t=t+c\)
\(
I=x^{x}+c
\)
Comparing with given data, we write \(k=1=\log _{e} e\)