MHT CET · Maths · Differentiation
If \(x=\log t, t>0\) and \(\mathrm{y}=\frac{1}{\mathrm{t}}\) then \(\frac{\mathrm{d}^2 \mathrm{y}}{\mathrm{d} x^2}=\)
- A \(\frac{\mathrm{dy}}{\mathrm{d} x}\)
- B \(\frac{-\mathrm{dy}}{\mathrm{d} x}\)
- C 2y
- D \(\frac{\mathrm{y}}{x}\)
Answer & Solution
Correct Answer
(B) \(\frac{-\mathrm{dy}}{\mathrm{d} x}\)
Step-by-step Solution
Detailed explanation
\(\frac{\mathrm{d}x}{\mathrm{d}t} = \frac{1}{t}\) \(\frac{\mathrm{d}y}{\mathrm{d}t} = -\frac{1}{t^2}\)
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