MHT CET · Maths · Differentiation
If \(x=\mathrm{t}^2+\mathrm{t}+1, \mathrm{y}=\sin \left(\frac{\mathrm{t} \pi}{2}\right)+\cos \left(\frac{\mathrm{t} \pi}{2}\right)\), then \(\frac{\mathrm{dy}}{\mathrm{d} x}\) at \(\mathrm{t}=1\) is
- A \(\frac{\pi}{3}\)
- B \(\frac{-\pi}{4}\)
- C \(\frac{\pi}{2}\)
- D \(\frac{-\pi}{6}\)
Answer & Solution
Correct Answer
(D) \(\frac{-\pi}{6}\)
Step-by-step Solution
Detailed explanation
\( \frac{\mathrm{dx}}{\mathrm{dt}} = 2\mathrm{t}+1 \) \( \frac{\mathrm{dx}}{\mathrm{dt}} \Big|_{\mathrm{t}=1} = 2(1)+1=3 \)
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