MHT CET · Maths · Application of Derivatives
If \(x=t^2\) and \(y=2 t\) are parametric equations of a curve, then equation of the normal to the curve at \(t=2\) is
- A \(2 x+y-12=0\)
- B \(x+y-8=0\)
- C \(x+2 y-12=0\)
- D \(2 x+3 y-20=0\)
Answer & Solution
Correct Answer
(A) \(2 x+y-12=0\)
Step-by-step Solution
Detailed explanation
Equation of normal at \(t\)
\(\begin{aligned}
& (y-2 t)=\frac{-\mathrm{d} x}{\mathrm{~d} t}\left(x-t^2\right) \\
& \Rightarrow(y-2 t)=\frac{-2 t}{2}\left(x-t^2\right) \\
& \Rightarrow(y-4)=-2(x-4)[\text { for } t=2] \\
& \Rightarrow 2 x+y-12=0
\end{aligned}\)
\(\begin{aligned}
& (y-2 t)=\frac{-\mathrm{d} x}{\mathrm{~d} t}\left(x-t^2\right) \\
& \Rightarrow(y-2 t)=\frac{-2 t}{2}\left(x-t^2\right) \\
& \Rightarrow(y-4)=-2(x-4)[\text { for } t=2] \\
& \Rightarrow 2 x+y-12=0
\end{aligned}\)
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